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1956 Curtis Cup

The 9th Curtis Cup Match was played on 8 and 9 June 1956 at Prince's Golf Club in Sandwich, Kent, England. The British Isles won by 5 matches to 4, to win the Curtis Cup for the second time.[1]

The United States won two of the three foursomes matches but the British Isles won four of the six singles to win by five matches to four.[2][1][3]

Format

The contest was played over two days, with three foursomes on the first day and six singles matches on the second day, a total of 9 points. Matches were over 36 holes.

Each of the 9 matches was worth one point in the larger team competition. If a match was all square after the 18th hole extra holes were not played. Rather, each side earned 12 a point toward their team total. The team that accumulated at least 5 points won the competition.

Teams

Howard did not play in any matches

[4]

Friday's foursomes matches

18-hole scores: Valentine/Garvey & Lesser/Smith all square, Smith/Price 2 up, Robertson/Anstey 2 up

Saturday's singles matches

18-hole scores: Lesser 2 up, W. Smith 2 up, F. Smith/Riley all square, Romack 2 up, Ward 5 up, Price 9 up

References

  1. ^ a b "Britain wins Curtis Cup through singles superiority". The Glasgow Herald. 11 June 1956. p. 4.
  2. ^ "U.S. lead in Curtis Cup". The Glasgow Herald. 9 June 1956. p. 5.
  3. ^ "The Curtis Cup in a British home" (PDF). USGA Journal and Turf Management: 10. July 1956.
  4. ^ "Curtis Cup teams" (PDF). USGA Journal and Turf Management: 16. April 1956.

51°17′46″N 1°22′12″E / 51.296°N 1.370°E / 51.296; 1.370