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1960 United States House of Representatives elections

The 1960 United States House of Representatives elections was an election for the United States House of Representatives on November 8, 1960, to elect members to serve in the 87th United States Congress. They coincided with the election of President John F. Kennedy and was the first house election to feature all 50 current U.S. states.

There were 437 seats, the most in U.S. history: 435 from the reapportionment in accordance with the 1950 census, and one seat for each of the new states of Alaska and Hawaii.

Although Democrats retained control, it was the first time since 1908 that an incoming president's party lost seats in the House, which would not happen again until 1988.

This was the most recent election cycle in which no new female representatives were elected to the House.

Overall results

Source: Election Statistics - Office of the Clerk

Special elections

In these special elections, the winner was seated during 1960 or before January 3, 1961; ordered by election date, then state, then district.

Alabama

Alaska

Borough Results

Arizona

Arkansas

California

Colorado

Connecticut

Delaware

Florida

Georgia

Hawaii

Idaho

Illinois

Indiana

Iowa

Kansas

Kentucky

Louisiana

Maine

Maryland

Massachusetts

Michigan

Minnesota

Mississippi

Missouri

Montana

Nebraska

Nevada

New Hampshire

New Jersey

New Mexico

New York

North Carolina

North Dakota

Ohio

Oklahoma

Oregon

Pennsylvania

Rhode Island

South Carolina

South Dakota

Tennessee

Texas

Utah

Vermont

Results by county

Virginia

Washington

West Virginia

Wisconsin

Wyoming

See also

References

  1. ^ a b "PA - District 18 - History" – via OurCampaigns.com.
  2. ^ "Our Campaigns - OH District 6 - Special Election Race - Nov 08, 1960". www.ourcampaigns.com.
  3. ^ "WA - District 03 - History" – via OurCampaigns.com.